(-1/5)^3+2q^2+160q-200=0

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Solution for (-1/5)^3+2q^2+160q-200=0 equation: 


q in (-oo:+oo)

2*q^2+160*q+(-1/5)^3-200 = 0

2*q^2+160*q-25001/125 = 0

DELTA = 160^2-(-25001/125*2*4)

DELTA = 3400008/125

DELTA > 0

q = ((3400008/125)^(1/2)-160)/(2*2) or q = (-(3400008/125)^(1/2)-160)/(2*2)

q = ((3400008/125)^(1/2)-160)/4 or q = (-((3400008/125)^(1/2)+160))/4

q in { (-((3400008/125)^(1/2)+160))/4, ((3400008/125)^(1/2)-160)/4 }

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